JEE Main 2003 Physics question
A nucleus with emits the following in a sequence: . Then Z of the resulting nucleus is
Answer: (2)
Solution
Count the emissions: α-particles: 1 + 5 + 1 + 1 = 8 (each lowers Z by 2: −16); β⁻: 4 (each raises Z by 1: +4); β⁺: 2 (each lowers Z by
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