JEE Main 2005 Physics question
The relation between time and distance is where and are constants. The acceleration is
Answer: (3)
Solution
. Differentiating w.r.t. : \frac{1}{v^2}$ = 2a =
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account