JEE Main 2005 Physics question
When two tuning forks (fork 1 and fork 2) are sounded simultaneously, 4 beats per second are heard. Now, some tape is attached on the prong of the fork 2 . When the tuning forks are sounded again, 6 beats per seconds are heard. If the frequency of fork 1 is 200 Hz, then what was the original frequency of fork 2 ?
Answer: (3)
Solution
Fork 2 is 196 or 204 Hz. Tape loads fork 2 and lowers its frequency. If it were 204 Hz, beats would decrease
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account