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JEE Main 2006 Physics question

PhysicsWork, Energy and PowerJEE Main 2006

The potential energy of a 1 kg particle free move along the x-axis is given by

V(x) = ( - )J

The total mechanical energy of the particle 2 J. Then, the maximum speed (in m/s ) is

Answer: (2)

Solution

Maximum speed occurs at minimum potential energy: , giving $ = Missing argument for \frac\frac14 -

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Question ID VK-038743