JEE Main 2006 Physics question
The resistance of a bulb filament is 100Ω at a temperature of C. If its temperature coefficient of resistance be 0.005 per °C, its resistance will become 200Ω at a temperature of
Answer: (3)
Solution
With (α defined with respect to 0°C): $ = = ⇒ 1 + 0.005t = 3 ⇒ t
See the full step-by-step solution
Create a free account to read the complete working, and practise questions like this in a timed test.
Create a free account