The differential equation whose solution is Ax^2 + By^2 = 1, where A and B are arbitrary constants is of

JEE Main 2006 Mathematics question

The differential equation whose solution is , where A and B are arbitrary constants is of

Answer: (4)

Two arbitrary constants give a second-order equation. Differentiating: , and again $A + B(y'^2 +

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Question ID VK-038879