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JEE Main 2006 Mathematics question

MathematicsVector AlgebraJEE Main 2006

is a triangle, right angled at . The resultant of the forces acting along , with magnitudes and respectively is the force along , where D is the foot of the perpendicular from A onto BC. The magnitude of the resultant is

Answer: (4)

Solution

The forces are perpendicular: \sqrt{\frac{1}{AB^2} + \frac{1}{AC^2}}\frac{\sqrt{AB^2 + AC^2}}{AB· AC}$ =

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Question ID VK-038880