JEE Main 2008 Physics question
A parallel plate capacitor with air between the plates has a capacitance of 9pF. The separation between its plates is ' '. The space between the plates is now filled with two dielectrics. One of the dielectrics has dielectric constant and thickness while the other one has dielectric constant and thickness . Capacitance of the capacitor is now
Answer: (3)
Solution
The two layers are in series: \frac{ε_0A}{\frac{d/3}{3} + \frac{2d/3}{6}}$ =
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