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JEE Main 2008 Chemistry question

ChemistrySolutionsJEE Main 2008

At 80°C, the vapour pressure of pure liquid ' ' is 520 mmHg and that of pure liquid ' ' is 1000 mm Hg. If a mixture solution of ' ' and ' ' boils at 80°C and 1 atm pressure, the amount of ' ' in the mixture is (1 atm = 760 mmHg)

Answer: (4)

Solution

Boiling at 80°C under 1 atm means the total vapour pressure is 760 mmHg: $ + 1000(1 -

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Question ID VK-039061