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JEE Main 2008 Chemistry question

ChemistryElectrochemistryJEE Main 2008

Given , . The potential for the cell Cr|Cr^{3+}(0.1M)||Fe^{2+}(0.01M)|Fe is

Answer: (1)

Solution

V. Reaction 2Cr + 3Fe^{2+} \to 2Cr^{3+} + 3Fe, n = 6. $E = 0.30 -

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Question ID VK-039063