JEE Main 2009 Chemistry question

ChemistryThermodynamicsJEE Main 2009

On the basis of the following thermochemical data:

) → + ;\ Δ H = 57.32\ kJ

+ Missing argument for \frac\frac → );\ Δ H = -286.20\ kJ

The value of enthalpy of formation of ion at 25°C is:

Answer: (2)

Solution

Adding the two equations: , $Δ H = -286.20 +

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Question ID VK-039146