JEE Main 2010 Physics question
A radioactive nucleus (initial mass number A and atomic number Z) emits 3α-particles and 2 positrons. The ratio of number of neutrons to that of protons in the final nucleus will be
Answer: (2)
Solution
3α: A → A − 12, Z → Z − 6. Each positron emission lowers Z by 1: Z → Z − 8.
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