JEE Main 2010 Mathematics question

MathematicsApplication of DerivativesJEE Main 2010

Let be a continuous function defined by . Statement-1: , for some . Statement-2: , for all

Answer: (4)

Solution

By AM–GM, , so , with the maximum attained and as — Statement 2 true. Since f is continuous and $Missing argument for \frac\frac13

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Question ID VK-039278