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JEE Main 2010 Mathematics question

MathematicsApplication of DerivativesJEE Main 2010

Let be defined by . If f has a local minimum at x = −1, then a possible value of k is

Answer: (3)

Solution

f(−1) = k + 2. On the left f decreases to k + 2; on the right f → 1 as x → −1⁺ and increases. For

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Question ID VK-039281