JEE Main 2011 Physics question

PhysicsElectrostatic Potential and CapacitanceJEE Main 2011

A resistor 'R' and 2μF capacitor in series is connected through a switch to 200 V direct supply. Across the capacitor is a neon bulb that lights up at 120 V. Calculate the value of R to make the bulb light up 5 s after the switch has been closed. ()

Answer: (2)

Solution

e^{-t/RC})e^{-t/RC}\frac{t}{RC}\ln$2.5 = 2.303×0.4 =

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Question ID VK-039309