JEE Main 2011 Chemistry question
The hybridization of orbitals of N atom in , and are respectively :
Answer: (1)
Solution
: 3 σ-bonds, no lone pair — (trigonal planar). : 2 σ-bonds, linear — sp. : 4 σ-bonds — . Option (1).
The hybridization of orbitals of N atom in , and are respectively :
: 3 σ-bonds, no lone pair — (trigonal planar). : 2 σ-bonds, linear — sp. : 4 σ-bonds — . Option (1).